(1/x)+(1/x+3)=(1/4)

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Solution for (1/x)+(1/x+3)=(1/4) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x+3 = 1/4 // - 1/4

1/x+1/x-(1/4)+3 = 0

1/x+1/x-1/4+3 = 0

2*x^-1 = -11/4 // : 2

x^-1 = -11/8

-1 < 0

1/(x^1) = -11/8 // * x^1

1 = -11/8*x^1 // : -11/8

-8/11 = x^1

x = -8/11

x = -8/11

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