(1/x)+(1/x+4)=1/5

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Solution for (1/x)+(1/x+4)=1/5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x+4 = 1/5 // - 1/5

1/x+1/x-(1/5)+4 = 0

1/x+1/x-1/5+4 = 0

2*x^-1 = -19/5 // : 2

x^-1 = -19/10

-1 < 0

1/(x^1) = -19/10 // * x^1

1 = -19/10*x^1 // : -19/10

-10/19 = x^1

x = -10/19

x = -10/19

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