(1/x)+(2/5)=(3/2x)

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Solution for (1/x)+(2/5)=(3/2x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+2/5 = (3/2)*x // - (3/2)*x

1/x-((3/2)*x)+2/5 = 0

(-3/2)*x+1/x+2/5 = 0

1*x^-1-3/2*x^1+2/5*x^0 = 0

(2/5*x^1-3/2*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(2/5*x^1-3/2*x^2+1*x^0) = 0

x^1

(-3/2)*x^2+(2/5)*x+1 = 0

(-3/2)*x^2+(2/5)*x+1 = 0

DELTA = (2/5)^2-(1*4*(-3/2))

DELTA = 154/25

DELTA > 0

x = ((154/25)^(1/2)-(2/5))/(2*(-3/2)) or x = (-(2/5)-(154/25)^(1/2))/(2*(-3/2))

x = ((154/25)^(1/2)-2/5)/(-3) or x = ((154/25)^(1/2)+2/5)/3

x in { ((154/25)^(1/2)-2/5)/(-3), ((154/25)^(1/2)+2/5)/3} 

x in { ((154/25)^(1/2)-2/5)/(-3), ((154/25)^(1/2)+2/5)/3 }

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