(1/x)+(6/2x)

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Solution for (1/x)+(6/2x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(6/2)*x+1/x = 0

3*x^1+1*x^-1 = 0

(3*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2+1*x^0) = 0

x^1

3*x^2+1 = 0

3*x^2+1 = 0

DELTA = 0^2-(1*3*4)

DELTA = -12

DELTA < 0

x in { } 

x belongs to the empty set

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