(1/x)+2x

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Solution for (1/x)+2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+1/x = 0

2*x^1+1*x^-1 = 0

(2*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+1*x^0) = 0

x^1

2*x^2+1 = 0

2*x^2+1 = 0

DELTA = 0^2-(1*2*4)

DELTA = -8

DELTA < 0

x in { } 

x belongs to the empty set

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