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(1/x)+3=(1/2)
We move all terms to the left:
(1/x)+3-((1/2))=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/x)+3-((+1/2))=0
We get rid of parentheses
1/x+3-((+1/2))=0
We calculate fractions
()/2x^2+(-((+1*x)/2x^2+3=0
We add all the numbers together, and all the variables
()/2x^2+(-((+x)/2x^2+3=0
We calculate fractions
We do not support expression: x^4
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