(1/x)+x=2

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Solution for (1/x)+x=2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+1/x = 2 // - 2

x+1/x-2 = 0

1*x^1+1*x^-1-2*x^0 = 0

(1*x^2-2*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-2*x^1+1*x^0) = 0

x^1

x^2-2*x+1 = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

x in { 1, 1}

x in { 1, 1 }

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