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(1/x)-(1/3)=(1/3(x))
We move all terms to the left:
(1/x)-(1/3)-((1/3(x)))=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/x)-((+1/3x))-(+1/3)=0
We get rid of parentheses
1/x-((+1/3x))-1/3=0
We calculate fractions
9x/9x^2+(-((+1*x)/9x^2+(-x)/9x^2=0
We can not solve this equation
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