(1/x)-(1/3*x)=6

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Solution for (1/x)-(1/3*x)=6 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-((1/3)*x) = 6 // - 6

1/x-((1/3)*x)-6 = 0

(-1/3)*x+1/x-6 = 0

1*x^-1-1/3*x^1-6*x^0 = 0

(1*x^0-1/3*x^2-6*x^1)/(x^1) = 0 // * x^2

x^1*(1*x^0-1/3*x^2-6*x^1) = 0

x^1

(-1/3)*x^2-6*x+1 = 0

(-1/3)*x^2-6*x+1 = 0

DELTA = (-6)^2-(1*4*(-1/3))

DELTA = 112/3

DELTA > 0

x = ((112/3)^(1/2)+6)/(2*(-1/3)) or x = (6-(112/3)^(1/2))/(2*(-1/3))

x = -3/2*((112/3)^(1/2)+6) or x = -3/2*(6-(112/3)^(1/2))

x in { -3/2*((112/3)^(1/2)+6), -3/2*(6-(112/3)^(1/2))}

x in { -3/2*((112/3)^(1/2)+6), -3/2*(6-(112/3)^(1/2)) }

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