(1/x)-(1/3x)=(1/2x)+(1/6x)

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Solution for (1/x)-(1/3x)=(1/2x)+(1/6x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-((1/3)*x) = (1/2)*x+(1/6)*x // - (1/2)*x+(1/6)*x

1/x-((1/3)*x)-((1/2)*x)-((1/6)*x) = 0

(-1/3)*x+(-1/2)*x+(-1/6)*x+1/x = 0

1*x^-1-1*x^1 = 0

(1*x^0-1*x^2)/(x^1) = 0 // * x^2

x^1*(1*x^0-1*x^2) = 0

x^1

1-x^2 = 0

1-x^2 = 0

DELTA = 0^2-(-1*1*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)+0)/(-1*2) or x = (0-4^(1/2))/(-1*2)

x = -1 or x = 1

x in { -1, 1} 

x in { -1, 1 }

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