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(1/x)-(1/5x)+(1/x+1)=(5/2x)
We move all terms to the left:
(1/x)-(1/5x)+(1/x+1)-((5/2x))=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x+1)!=0
x∈R
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/x)-(+1/5x)+(1/x+1)-((+5/2x))=0
We get rid of parentheses
1/x-1/5x+1/x-((+5/2x))+1=0
We calculate fractions
We do not support expression: x^3
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