(1/x)-(1/x-16)=1/4

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Solution for (1/x)-(1/x-16)=1/4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-(1/x)+16 = 1/4 // - 1/4

1/x-(1/x)-(1/4)+16 = 0

1/x-x^-1-1/4+16 = 0

63/4 = 0

x belongs to the empty set

x belongs to the empty set

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