(1/x)-(3/2)=7/x

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Solution for (1/x)-(3/2)=7/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-(3/2) = 7/x // - 7/x

1/x-(7/x)-(3/2) = 0

1/x-7*x^-1-3/2 = 0

-6*x^-1 = 3/2 // : -6

x^-1 = -1/4

-1 < 0

1/(x^1) = -1/4 // * x^1

1 = -1/4*x^1 // : -1/4

-4 = x^1

x = -4

x = -4

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