(1/x)=(1/32)-(1/(200-x))

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Solution for (1/x)=(1/32)-(1/(200-x)) equation:


D( x )

x = 0

200-x = 0

x = 0

x = 0

200-x = 0

200-x = 0

200-x = 0 // - 200

-x = -200 // * -1

x = 200

x in (-oo:0) U (0:200) U (200:+oo)

1/x = 1/32-(1/(200-x)) // - 1/32-(1/(200-x))

1/(200-x)+1/x-(1/32) = 0

1/(200-x)+1/x-1/32 = 0

(1*32*x)/(32*x*(200-x))+(1*32*(200-x))/(32*x*(200-x))+(-1*x*(200-x))/(32*x*(200-x)) = 0

1*32*(200-x)-1*x*(200-x)+1*32*x = 0

x^2-200*x+6400 = 0

x^2-200*x+6400 = 0

x^2-200*x+6400 = 0

DELTA = (-200)^2-(1*4*6400)

DELTA = 14400

DELTA > 0

x = (14400^(1/2)+200)/(1*2) or x = (200-14400^(1/2))/(1*2)

x = 160 or x = 40

(x-40)*(x-160) = 0

((x-40)*(x-160))/(32*x*(200-x)) = 0

((x-40)*(x-160))/(32*x*(200-x)) = 0 // * 32*x*(200-x)

(x-40)*(x-160) = 0

( x-160 )

x-160 = 0 // + 160

x = 160

( x-40 )

x-40 = 0 // + 40

x = 40

x in { 160, 40 }

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