(1/x)=(1/5)+(3/2x)

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Solution for (1/x)=(1/5)+(3/2x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x = (3/2)*x+1/5 // - (3/2)*x+1/5

1/x-((3/2)*x)-(1/5) = 0

(-3/2)*x+1/x-1/5 = 0

1*x^-1-3/2*x^1-1/5*x^0 = 0

(1*x^0-3/2*x^2-1/5*x^1)/(x^1) = 0 // * x^2

x^1*(1*x^0-3/2*x^2-1/5*x^1) = 0

x^1

(-3/2)*x^2+(-1/5)*x+1 = 0

(-3/2)*x^2+(-1/5)*x+1 = 0

DELTA = (-1/5)^2-(1*4*(-3/2))

DELTA = 151/25

DELTA > 0

x = ((151/25)^(1/2)-(-1/5))/(2*(-3/2)) or x = (-(-1/5)-(151/25)^(1/2))/(2*(-3/2))

x = ((151/25)^(1/2)+1/5)/(-3) or x = (1/5-(151/25)^(1/2))/(-3)

x in { ((151/25)^(1/2)+1/5)/(-3), (1/5-(151/25)^(1/2))/(-3)} 

x in { ((151/25)^(1/2)+1/5)/(-3), (1/5-(151/25)^(1/2))/(-3) }

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