(1/x+1)+3=7/x+1

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Solution for (1/x+1)+3=7/x+1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1+3 = 7/x+1 // - 7/x+1

1/x-(7/x)-1+1+3 = 0

1/x-7*x^-1-1+1+3 = 0

-6*x^-1 = -3 // : -6

x^-1 = 1/2

-1 < 0

1/(x^1) = 1/2 // * x^1

1 = 1/2*x^1 // : 1/2

2 = x^1

x = 2

x = 2

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