(1/x+2)+(7/x-3)=4

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Solution for (1/x+2)+(7/x-3)=4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+7/x-3+2 = 4 // - 4

1/x+7/x-4-3+2 = 0

8*x^-1 = 5 // : 8

x^-1 = 5/8

-1 < 0

1/(x^1) = 5/8 // * x^1

1 = 5/8*x^1 // : 5/8

8/5 = x^1

x = 8/5

x = 8/5

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