(1/x+3)+(1/x+2)=1

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Solution for (1/x+3)+(1/x+2)=1 equation: 



(1/x+3)+(1/x+2)=1

We move all terms to the left:

(1/x+3)+(1/x+2)-(1)=0



Domain of the equation: x+3)!=0

x∈R





Domain of the equation: x+2)!=0

x∈R



We get rid of parentheses

1/x+1/x+3+2-1=0

We multiply all the terms by the denominator


3*x+2*x-1*x+1+1=0

We add all the numbers together, and all the variables

4x+2=0

We move all terms containing x to the left, all other terms to the right

4x=-2

x=-2/4

x=-1/2

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