(1/x+6)+(1/x+1)+(1/2x)=1/x

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Solution for (1/x+6)+(1/x+1)+(1/2x)=1/x equation:



(1/x+6)+(1/x+1)+(1/2x)=1/x
We move all terms to the left:
(1/x+6)+(1/x+1)+(1/2x)-(1/x)=0
Domain of the equation: x+6)!=0
x∈R
Domain of the equation: x+1)!=0
x∈R
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(1/x+6)+(1/x+1)+(+1/2x)-(+1/x)=0
We get rid of parentheses
1/x+1/x+1/2x-1/x+6+1=0
We calculate fractions
(-2x+2)/2x^2+x/2x^2+6+1=0
We add all the numbers together, and all the variables
(-2x+2)/2x^2+x/2x^2+7=0
We multiply all the terms by the denominator
(-2x+2)+x+7*2x^2=0
We add all the numbers together, and all the variables
x+(-2x+2)+7*2x^2=0
Wy multiply elements
14x^2+x+(-2x+2)=0
We get rid of parentheses
14x^2+x-2x+2=0
We add all the numbers together, and all the variables
14x^2-1x+2=0
a = 14; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·14·2
Δ = -111
Delta is less than zero, so there is no solution for the equation

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