(1/x-2)-(2/x+1)=(3/x-2)

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Solution for (1/x-2)-(2/x+1)=(3/x-2) equation: 



(1/x-2)-(2/x+1)=(3/x-2)

We move all terms to the left:

(1/x-2)-(2/x+1)-((3/x-2))=0



Domain of the equation: x-2)!=0

x∈R





Domain of the equation: x+1)!=0

x∈R





Domain of the equation: x-2))!=0

x∈R



We get rid of parentheses

1/x-2/x-((3/x-2))-2-1=0

We calculate fractions


(-2x)/x^2+(-((3*x)/x^2-2-1=0

We add all the numbers together, and all the variables

(-2x)/x^2+(-((+3x)/x^2-2-1=0

We calculate fractions

We do not support expression: x^4

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