(1/x-5)+(2x/5-x)-1

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Solution for (1/x-5)+(2x/5-x)-1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/5-x+1/x-5-1 = 0

1*x^-1-3/5*x^1-6*x^0 = 0

(1*x^0-3/5*x^2-6*x^1)/(x^1) = 0 // * x^2

x^1*(1*x^0-3/5*x^2-6*x^1) = 0

x^1

(-3/5)*x^2-6*x+1 = 0

(-3/5)*x^2-6*x+1 = 0

DELTA = (-6)^2-(1*4*(-3/5))

DELTA = 192/5

DELTA > 0

x = ((192/5)^(1/2)+6)/(2*(-3/5)) or x = (6-(192/5)^(1/2))/(2*(-3/5))

x = -5/6*((192/5)^(1/2)+6) or x = -5/6*(6-(192/5)^(1/2))

x in { -5/6*((192/5)^(1/2)+6), -5/6*(6-(192/5)^(1/2))} 

x in { -5/6*((192/5)^(1/2)+6), -5/6*(6-(192/5)^(1/2)) }

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