(1/x-x/2)(2/x-x)=1/2

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Solution for (1/x-x/2)(2/x-x)=1/2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/x-(x/2))*(2/x-x) = 1/2 // - 1/2

(1/x-(x/2))*(2/x-x)-(1/2) = 0

(1/x-(x/2))*(2/x-x)-1/2 = 0

(x^-1-1/2*x)*(2*x^-1-x)-1/2 = 0

(2*(x^-1-1/2*x)*(2*x^-1-x))/2-1/2 = 0

2*(x^-1-1/2*x)*(2*x^-1-x)-1 = 0

x^2+4*x^-2-5 = 0

x^2+4*x^-2-5 = 0

1*x^2+4*x^-2-5*x^0 = 0

(1*x^4-5*x^2+4*x^0)/(x^2) = 0 // * x^4

x^2*(1*x^4-5*x^2+4*x^0) = 0

x^2

x^4-5*x^2+4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

x^4-5*x^2+4 = 0

1

x-1

x^3+x^2-4*x-4

x^4-5*x^2+4

x-1

x^3-x^4

x^3-5*x^2+4

x^2-x^3

4-4*x^2

4*x^2-4*x

4-4*x

4*x-4

0

x^3+x^2-4*x-4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

x^3+x^2-4*x-4 = -6

1

-1

x = -1

x^3+x^2-4*x-4 = 0

-1

x+1

x^2-4

x^3+x^2-4*x-4

x+1

-x^3-x^2

-4*x-4

4*x+4

0

x^2-4 = 0

DELTA = 0^2-(-4*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+0)/(1*2) or x = (0-16^(1/2))/(1*2)

x = 2 or x = -2

x in { -2, 2, 1, -1}

(x+2)*(x-2)*(x-1)*(x+1) = 0

((x+2)*(x-2)*(x-1)*(x+1))/2 = 0

((x+2)*(x-2)*(x-1)*(x+1))/2 = 0 // * 2

(x+2)*(x-2)*(x-1)*(x+1) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+2 )

x+2 = 0 // - 2

x = -2

( x-1 )

x-1 = 0 // + 1

x = 1

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -1, -2, 1, 2 }

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