(1/y)+(1/28)=(1/21)

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Solution for (1/y)+(1/28)=(1/21) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y+1/28 = 1/21 // - 1/21

1/y+1/28-(1/21) = 0

1/y+1/28-1/21 = 0

1*y^-1 = 1/84 // : 1

y^-1 = 1/84

-1 < 0

1/(y^1) = 1/84 // * y^1

1 = 1/84*y^1 // : 1/84

84 = y^1

y = 84

y = 84

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