(1/y+2)+(1/y+6)=1

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Solution for (1/y+2)+(1/y+6)=1 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y+1/y+2+6 = 1 // - 1

1/y+1/y-1+2+6 = 0

2*y^-1 = -7 // : 2

y^-1 = -7/2

-1 < 0

1/(y^1) = -7/2 // * y^1

1 = -7/2*y^1 // : -7/2

-2/7 = y^1

y = -2/7

y = -2/7

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