(1/y-5)+(1/6)=(-6/2y-10)

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Solution for (1/y-5)+(1/6)=(-6/2y-10) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y+1/6-5 = (-6/2)*y-10 // - (-6/2)*y-10

1/y-((-6/2)*y)+1/6-5+10 = 0

3*y+1/y+1/6-5+10 = 0

3*y^1+1*y^-1+31/6*y^0 = 0

(3*y^2+31/6*y^1+1*y^0)/(y^1) = 0 // * y^2

y^1*(3*y^2+31/6*y^1+1*y^0) = 0

y^1

3*y^2+(31/6)*y+1 = 0

3*y^2+(31/6)*y+1 = 0

DELTA = (31/6)^2-(1*3*4)

DELTA = 529/36

DELTA > 0

y = ((529/36)^(1/2)-(31/6))/(2*3) or y = (-(31/6)-(529/36)^(1/2))/(2*3)

y = -2/9 or y = -3/2

y in { -3/2, -2/9} 

y in { -3/2, -2/9 }

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