(1/z)-(1/2z)-(1/5z)=(10/(z+1))

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Solution for (1/z)-(1/2z)-(1/5z)=(10/(z+1)) equation: 



(1/z)-(1/2z)-(1/5z)=(10/(z+1))

We move all terms to the left:

(1/z)-(1/2z)-(1/5z)-((10/(z+1)))=0



Domain of the equation: z)!=0

z!=0/1

z!=0

z∈R





Domain of the equation: 2z)!=0

z!=0/1

z!=0

z∈R





Domain of the equation: 5z)!=0

z!=0/1

z!=0

z∈R





Domain of the equation: (z+1)))!=0

z∈R



We add all the numbers together, and all the variables

(+1/z)-(+1/2z)-(+1/5z)-((10/(z+1)))=0

We get rid of parentheses

1/z-1/2z-1/5z-((10/(z+1)))=0

We calculate fractions

We do not support ezpression: z^4

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