(10(3)+32)=(7y+6)

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Solution for (10(3)+32)=(7y+6) equation: 



(10(3)+32)=(7y+6)

We move all terms to the left:

(10(3)+32)-((7y+6))=0

We add all the numbers together, and all the variables

-((7y+6))+135=0



We calculate terms in parentheses: -((7y+6)), so:

(7y+6)

We get rid of parentheses

7y+6

Back to the equation:

-(7y+6)



We get rid of parentheses

-7y-6+135=0

We add all the numbers together, and all the variables

-7y+129=0

We move all terms containing y to the left, all other terms to the right

-7y=-129

y=-129/-7

y=18+3/7

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