(10(9x-x)+x)(10x+9-x)=27

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Solution for (10(9x-x)+x)(10x+9-x)=27 equation: 



10(9x-x)+x10x+9-x=27

We move all terms to the left:

10(9x-x)+x10x+9-x-(27)=0

We add all the numbers together, and all the variables

10(+8x)+x10x-x+9-27=0

We add all the numbers together, and all the variables

-1x+10(+8x)+x10x-18=0

We multiply parentheses

-1x+80x+x10x-18=0

We add all the numbers together, and all the variables

79x+x10x-18=0

We move all terms containing x to the left, all other terms to the right

79x+x10x=18

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