(10)/(m)+(6)/(m+3)+4=5

Solution for (10)/(m)+(6)/(m+3)+4=5 equation:

(10)/(m)+(6)/(m+3)+4=5

We move all terms to the left:

(10)/(m)+(6)/(m+3)+4-(5)=0


Domain of the equation: m!=0

m∈R



Domain of the equation: (m+3)!=0

We move all terms containing m to the left, all other terms to the right

m!=-3

m∈R


We add all the numbers together, and all the variables

10/m+6/(m+3)-1=0

We calculate fractions


(10m+30)/(m^2+3m)+6m/(m^2+3m)-1=0

We multiply all the terms by the denominator


(10m+30)+6m-1*(m^2+3m)=0

We add all the numbers together, and all the variables

6m+(10m+30)-1*(m^2+3m)=0

We get rid of parentheses

6m+10m-1*(m^2+3m)+30=0

We add all the numbers together, and all the variables

16m-1*(m^2+3m)+30=0

We move all terms containing m to the left, all other terms to the right

16m-1*(m^2+3m)=-30