(10)/(m)+(6)/(m+3)+4=5

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Solution for (10)/(m)+(6)/(m+3)+4=5 equation:



(10)/(m)+(6)/(m+3)+4=5
We move all terms to the left:
(10)/(m)+(6)/(m+3)+4-(5)=0
Domain of the equation: m!=0
m∈R
Domain of the equation: (m+3)!=0
We move all terms containing m to the left, all other terms to the right
m!=-3
m∈R
We add all the numbers together, and all the variables
10/m+6/(m+3)-1=0
We calculate fractions
(10m+30)/(m^2+3m)+6m/(m^2+3m)-1=0
We multiply all the terms by the denominator
(10m+30)+6m-1*(m^2+3m)=0
We add all the numbers together, and all the variables
6m+(10m+30)-1*(m^2+3m)=0
We get rid of parentheses
6m+10m-1*(m^2+3m)+30=0
We add all the numbers together, and all the variables
16m-1*(m^2+3m)+30=0
We move all terms containing m to the left, all other terms to the right
16m-1*(m^2+3m)=-30

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