(10+20x)/2+4x=47

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Solution for (10+20x)/2+4x=47 equation:



(10+20x)/2+4x=47
We move all terms to the left:
(10+20x)/2+4x-(47)=0
We add all the numbers together, and all the variables
(20x+10)/2+4x-47=0
We add all the numbers together, and all the variables
4x+(20x+10)/2-47=0
We multiply all the terms by the denominator
4x*2+(20x+10)-47*2=0
We add all the numbers together, and all the variables
4x*2+(20x+10)-94=0
Wy multiply elements
8x+(20x+10)-94=0
We get rid of parentheses
8x+20x+10-94=0
We add all the numbers together, and all the variables
28x-84=0
We move all terms containing x to the left, all other terms to the right
28x=84
x=84/28
x=3

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