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(10+2x)(18+2x)-180=0
We add all the numbers together, and all the variables
(2x+10)(2x+18)-180=0
We multiply parentheses ..
(+4x^2+36x+20x+180)-180=0
We get rid of parentheses
4x^2+36x+20x+180-180=0
We add all the numbers together, and all the variables
4x^2+56x=0
a = 4; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·4·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*4}=\frac{-112}{8} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*4}=\frac{0}{8} =0 $
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