(10+2x)(4x-8)=0

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Solution for (10+2x)(4x-8)=0 equation:



(10+2x)(4x-8)=0
We add all the numbers together, and all the variables
(2x+10)(4x-8)=0
We multiply parentheses ..
(+8x^2-16x+40x-80)=0
We get rid of parentheses
8x^2-16x+40x-80=0
We add all the numbers together, and all the variables
8x^2+24x-80=0
a = 8; b = 24; c = -80;
Δ = b2-4ac
Δ = 242-4·8·(-80)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-56}{2*8}=\frac{-80}{16} =-5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+56}{2*8}=\frac{32}{16} =2 $

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