(10+5x)+58=(11x+2)

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Solution for (10+5x)+58=(11x+2) equation: 



(10+5x)+58=(11x+2)

We move all terms to the left:

(10+5x)+58-((11x+2))=0

We add all the numbers together, and all the variables

(5x+10)-((11x+2))+58=0

We get rid of parentheses

5x-((11x+2))+10+58=0



We calculate terms in parentheses: -((11x+2)), so:

(11x+2)

We get rid of parentheses

11x+2

Back to the equation:

-(11x+2)



We add all the numbers together, and all the variables

5x-(11x+2)+68=0

We get rid of parentheses

5x-11x-2+68=0

We add all the numbers together, and all the variables

-6x+66=0

We move all terms containing x to the left, all other terms to the right

-6x=-66

x=-66/-6

x=+11

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