(10+5x-2)/2=(3x+1)/3

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Solution for (10+5x-2)/2=(3x+1)/3 equation: 



(10+5x-2)/2=(3x+1)/3

We move all terms to the left:

(10+5x-2)/2-((3x+1)/3)=0

We add all the numbers together, and all the variables

(5x+8)/2-((3x+1)/3)=0

We calculate fractions


5x/()+(-((3x+1)*2)/()=0



We calculate terms in parentheses: +(-((3x+1)*2)/(), so:

-((3x+1)*2)/(

We multiply all the terms by the denominator


-((3x+1)*2)



We calculate terms in parentheses: -((3x+1)*2), so:

(3x+1)*2

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

-6x-2

Back to the equation:

+(-6x-2)



We get rid of parentheses

5x/()-6x-2=0

We multiply all the terms by the denominator


5x-6x*()-2*()=0

We add all the numbers together, and all the variables

5x-6x*()=0

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