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(10+x)(14+x)=221
We move all terms to the left:
(10+x)(14+x)-(221)=0
We add all the numbers together, and all the variables
(x+10)(x+14)-221=0
We multiply parentheses ..
(+x^2+14x+10x+140)-221=0
We get rid of parentheses
x^2+14x+10x+140-221=0
We add all the numbers together, and all the variables
x^2+24x-81=0
a = 1; b = 24; c = -81;
Δ = b2-4ac
Δ = 242-4·1·(-81)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-30}{2*1}=\frac{-54}{2} =-27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+30}{2*1}=\frac{6}{2} =3 $
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