(10+x)=(4x-35)

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Solution for (10+x)=(4x-35) equation: 



(10+x)=(4x-35)

We move all terms to the left:

(10+x)-((4x-35))=0

We add all the numbers together, and all the variables

(x+10)-((4x-35))=0

We get rid of parentheses

x-((4x-35))+10=0



We calculate terms in parentheses: -((4x-35)), so:

(4x-35)

We get rid of parentheses

4x-35

Back to the equation:

-(4x-35)



We get rid of parentheses

x-4x+35+10=0

We add all the numbers together, and all the variables

-3x+45=0

We move all terms containing x to the left, all other terms to the right

-3x=-45

x=-45/-3

x=+15

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