(10-2x)+(9-2x)+(2x)+(x)=17

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Solution for (10-2x)+(9-2x)+(2x)+(x)=17 equation: 



(10-2x)+(9-2x)+(2x)+(x)=17

We move all terms to the left:

(10-2x)+(9-2x)+(2x)+(x)-(17)=0

We add all the numbers together, and all the variables

(-2x+10)+(-2x+9)+2x+x-17=0

We add all the numbers together, and all the variables

3x+(-2x+10)+(-2x+9)-17=0

We get rid of parentheses

3x-2x-2x+10+9-17=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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