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(10-3x)(2x-4)=-6x^2
We move all terms to the left:
(10-3x)(2x-4)-(-6x^2)=0
We add all the numbers together, and all the variables
-(-6x^2)+(-3x+10)(2x-4)=0
We get rid of parentheses
6x^2+(-3x+10)(2x-4)=0
We multiply parentheses ..
6x^2+(-6x^2+12x+20x-40)=0
We get rid of parentheses
6x^2-6x^2+12x+20x-40=0
We add all the numbers together, and all the variables
32x-40=0
We move all terms containing x to the left, all other terms to the right
32x=40
x=40/32
x=1+1/4
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