(10-3x)+(20-23x)=180

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Solution for (10-3x)+(20-23x)=180 equation: 



(10-3x)+(20-23x)=180

We move all terms to the left:

(10-3x)+(20-23x)-(180)=0

We add all the numbers together, and all the variables

(-3x+10)+(-23x+20)-180=0

We get rid of parentheses

-3x-23x+10+20-180=0

We add all the numbers together, and all the variables

-26x-150=0

We move all terms containing x to the left, all other terms to the right

-26x=150

x=150/-26

x=-5+10/13

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