(10-3y)/3=(15+5y)/2

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Solution for (10-3y)/3=(15+5y)/2 equation: 



(10-3y)/3=(15+5y)/2

We move all terms to the left:

(10-3y)/3-((15+5y)/2)=0

We add all the numbers together, and all the variables

(-3y+10)/3-((5y+15)/2)=0

We calculate fractions


(-3y)/()+(-((5y+15)*3)/()=0



We calculate terms in parentheses: +(-((5y+15)*3)/(), so:

-((5y+15)*3)/(

We multiply all the terms by the denominator


-((5y+15)*3)



We calculate terms in parentheses: -((5y+15)*3), so:

(5y+15)*3

We multiply parentheses

15y+45

Back to the equation:

-(15y+45)



We get rid of parentheses

-15y-45

Back to the equation:

+(-15y-45)



We get rid of parentheses

(-3y)/()-15y-45=0

We multiply all the terms by the denominator


(-3y)-15y*()-45*()=0

We add all the numbers together, and all the variables

(-3y)-15y*()=0

We get rid of parentheses

-3y-15y*()=0

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