(10-x)+(x+2)+(3x)+(2x-2)=360

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Solution for (10-x)+(x+2)+(3x)+(2x-2)=360 equation:


Simplifying
(10 + -1x) + (x + 2) + (3x) + (2x + -2) = 360

Remove parenthesis around (10 + -1x)
10 + -1x + (x + 2) + (3x) + (2x + -2) = 360

Reorder the terms:
10 + -1x + (2 + x) + (3x) + (2x + -2) = 360

Remove parenthesis around (2 + x)
10 + -1x + 2 + x + (3x) + (2x + -2) = 360

Reorder the terms:
10 + -1x + 2 + x + (3x) + (-2 + 2x) = 360

Remove parenthesis around (-2 + 2x)
10 + -1x + 2 + x + (3x) + -2 + 2x = 360

Reorder the terms:
10 + 2 + -2 + -1x + x + (3x) + 2x = 360

Combine like terms: 10 + 2 = 12
12 + -2 + -1x + x + (3x) + 2x = 360

Combine like terms: 12 + -2 = 10
10 + -1x + x + (3x) + 2x = 360

Combine like terms: -1x + x = 0
10 + 0 + (3x) + 2x = 360
10 + (3x) + 2x = 360

Combine like terms: (3x) + 2x = 5x
10 + 5x = 360

Solving
10 + 5x = 360

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 5x = 360 + -10

Combine like terms: 10 + -10 = 0
0 + 5x = 360 + -10
5x = 360 + -10

Combine like terms: 360 + -10 = 350
5x = 350

Divide each side by '5'.
x = 70

Simplifying
x = 70

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