(10-x)/10+(20-x/10)=24

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Solution for (10-x)/10+(20-x/10)=24 equation:



(10-x)/10+(20-x/10)=24
We move all terms to the left:
(10-x)/10+(20-x/10)-(24)=0
We add all the numbers together, and all the variables
(-1x+10)/10+(-x/10+20)-24=0
We get rid of parentheses
(-1x+10)/10-x/10+20-24=0
We multiply all the terms by the denominator
(-1x+10)-x+20*10-24*10=0
We add all the numbers together, and all the variables
-1x+(-1x+10)-40=0
We get rid of parentheses
-1x-1x+10-40=0
We add all the numbers together, and all the variables
-2x-30=0
We move all terms containing x to the left, all other terms to the right
-2x=30
x=30/-2
x=-15

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