(10-x)/5=(7-x)/2

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Solution for (10-x)/5=(7-x)/2 equation: 



(10-x)/5=(7-x)/2

We move all terms to the left:

(10-x)/5-((7-x)/2)=0

We add all the numbers together, and all the variables

(-1x+10)/5-((-1x+7)/2)=0

We calculate fractions


(-x)/()+(-((-1x+7)*5)/()=0



We calculate terms in parentheses: +(-((-1x+7)*5)/(), so:

-((-1x+7)*5)/(

We multiply all the terms by the denominator


-((-1x+7)*5)



We calculate terms in parentheses: -((-1x+7)*5), so:

(-1x+7)*5

We multiply parentheses

-5x+35

Back to the equation:

-(-5x+35)



We get rid of parentheses

5x-35

Back to the equation:

+(5x-35)



We add all the numbers together, and all the variables

(-1x)/()+(5x-35)=0

We get rid of parentheses

(-1x)/()+5x-35=0

We multiply all the terms by the denominator


(-1x)+5x*()-35*()=0

We add all the numbers together, and all the variables

(-1x)+5x*()=0

We get rid of parentheses

-1x+5x*()=0

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