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(10/3)x-(5/6)=(2/3)
We move all terms to the left:
(10/3)x-(5/6)-((2/3))=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+10/3)x-(+5/6)-((+2/3))=0
We multiply parentheses
10x^2-(+5/6)-((+2/3))=0
We get rid of parentheses
10x^2-5/6-((+2/3))=0
We calculate fractions
10x^2+()/()+()/()=0
We add all the numbers together, and all the variables
10x^2+2=0
a = 10; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·10·2
Δ = -80
Delta is less than zero, so there is no solution for the equation
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