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(10/4)x=0.25
We move all terms to the left:
(10/4)x-(0.25)=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+10/4)x-(0.25)=0
We add all the numbers together, and all the variables
(+10/4)x-0.25=0
We multiply parentheses
10x^2-0.25=0
a = 10; b = 0; c = -0.25;
Δ = b2-4ac
Δ = 02-4·10·(-0.25)
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10}}{2*10}=\frac{0-\sqrt{10}}{20} =-\frac{\sqrt{}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10}}{2*10}=\frac{0+\sqrt{10}}{20} =\frac{\sqrt{}}{20} $
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