(10/6)c+4/12=P

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Solution for (10/6)c+4/12=P equation: 



(10/6)c+4/12=

We move all terms to the left:

(10/6)c+4/12-()=0



Domain of the equation: 6)c!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(+10/6)c+4/12-()=0

We add all the numbers together, and all the variables

(+10/6)c+4/12=0

We multiply parentheses

10c^2+4/12=0

We multiply all the terms by the denominator


10c^2*12+4=0

Wy multiply elements

120c^2+4=0

a = 120; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·120·4
Δ = -1920
Delta is less than zero, so there is no solution for the equation

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