(10/x)-(3/(5x))=(2/(x+9))

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Solution for (10/x)-(3/(5x))=(2/(x+9)) equation:


D( x )

x = 0

x+9 = 0

5*x = 0

x = 0

x = 0

x+9 = 0

x+9 = 0

x+9 = 0 // - 9

x = -9

5*x = 0

5*x = 0

5*x = 0 // : 5

x = 0

x in (-oo:-9) U (-9:0) U (0:+oo)

10/x-(3/(5*x)) = 2/(x+9) // - 2/(x+9)

10/x-(2/(x+9))-(3/(5*x)) = 0

10/x-2*(x+9)^-1+(-3/5)*x^-1 = 0

10/x-2/(x+9)-3/(5*x) = 0

(-2*5*x*x)/(5*x*x*(x+9))+(5*10*x*(x+9))/(5*x*x*(x+9))+(-3*x*(x+9))/(5*x*x*(x+9)) = 0

5*10*x*(x+9)-3*x*(x+9)-2*5*x*x = 0

40*x^2-3*x^2+450*x-27*x = 0

37*x^2+423*x = 0

37*x^2+423*x = 0

x*(37*x+423) = 0

37*x+423 = 0 // - 423

37*x = -423 // : 37

x = -423/37

x*(x+423/37) = 0

(x*(x+423/37))/(5*x*x*(x+9)) = 0

(x*(x+423/37))/(5*x*x*(x+9)) = 0 // * 5*x*x*(x+9)

x*(x+423/37) = 0

( x+423/37 )

x+423/37 = 0 // - 423/37

x = -423/37

( x )

x = 0

x in { 0}

x = -423/37

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