(10/x)-60=(60/7x)

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Solution for (10/x)-60=(60/7x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x-60 = (60/7)*x // - (60/7)*x

10/x-((60/7)*x)-60 = 0

(-60/7)*x+10/x-60 = 0

10*x^-1-60/7*x^1-60*x^0 = 0

(10*x^0-60/7*x^2-60*x^1)/(x^1) = 0 // * x^2

x^1*(10*x^0-60/7*x^2-60*x^1) = 0

x^1

(-60/7)*x^2-60*x+10 = 0

(-60/7)*x^2-60*x+10 = 0

DELTA = (-60)^2-(4*10*(-60/7))

DELTA = 27600/7

DELTA > 0

x = ((27600/7)^(1/2)+60)/(2*(-60/7)) or x = (60-(27600/7)^(1/2))/(2*(-60/7))

x = -7/120*((27600/7)^(1/2)+60) or x = -7/120*(60-(27600/7)^(1/2))

x in { -7/120*((27600/7)^(1/2)+60), -7/120*(60-(27600/7)^(1/2))} 

x in { -7/120*((27600/7)^(1/2)+60), -7/120*(60-(27600/7)^(1/2)) }

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