(10/x+7)+(20/2x+8)=24/2x

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Solution for (10/x+7)+(20/2x+8)=24/2x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(20/2)*x+10/x+7+8 = (24/2)*x // - (24/2)*x

(20/2)*x-((24/2)*x)+10/x+7+8 = 0

(20/2)*x-12*x+10/x+7+8 = 0

10*x^-1-2*x^1+15*x^0 = 0

(15*x^1-2*x^2+10*x^0)/(x^1) = 0 // * x^2

x^1*(15*x^1-2*x^2+10*x^0) = 0

x^1

15*x-2*x^2+10 = 0

15*x-2*x^2+10 = 0

DELTA = 15^2-(-2*4*10)

DELTA = 305

DELTA > 0

x = (305^(1/2)-15)/(-2*2) or x = (-305^(1/2)-15)/(-2*2)

x = (305^(1/2)-15)/(-4) or x = (305^(1/2)+15)/4

x in { (305^(1/2)-15)/(-4), (305^(1/2)+15)/4}

x in { (305^(1/2)-15)/(-4), (305^(1/2)+15)/4 }

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