(10/x-2)(-5/x)=-3/x

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Solution for (10/x-2)(-5/x)=-3/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(-5/x)*(10/x-2) = -3/x // + -3/x

(-5/x)*(10/x-2)-(-3/x) = 0

(-5/x)*(10/x-2)+3*x^-1 = 0

3/x-5*x^-1*(10*x^-1-2) = 0

(-5*x^-1*x*(10*x^-1-2))/x+3/x = 0

3-5*x^-1*x*(10*x^-1-2) = 0

13-50*x^-1 = 0

(13-50*x^-1)/x = 0

(13-50*x^-1)/x = 0 // * x

13-50*x^-1 = 0

-50*x^-1 = -13 // : -50

x^-1 = 13/50

-1 < 0

1/(x^1) = 13/50 // * x^1

1 = 13/50*x^1 // : 13/50

50/13 = x^1

x = 50/13

x = 50/13

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